Distance from Charlottenlund to Truskaw
The distance between Charlottenlund, Denmark and Truskaw, Poland is 816 km (507 miles) in a straight line. If a road route exists, expect roughly 1019 km (633 miles) by car — around 12 h 44 min of driving.
| Measure | Value |
|---|---|
| Straight-line distance | 816 km / 507 mi |
| Road distance (estimate) | ≈ 1019 km / 633 mi |
| Driving time (estimate) | ≈ 12 h 44 min |
| Flight time (estimate) | ≈ 1 h 28 min |
Road distance and travel times are estimates based on the straight-line distance (road factor 1.25, average speed 80 km/h) — actual routes vary.
| Place | Latitude | Longitude |
|---|---|---|
| Charlottenlund, Denmark | 56.031955 | 9.965266 |
| Truskaw, Poland | 52.303577021 | 20.777313902 |
Frequently asked questions
How far is Truskaw from Charlottenlund?
The straight-line (air) distance from Charlottenlund, Denmark to Truskaw, Poland is 816 km (507 miles). By road it is roughly 1019 km (633 miles), depending on the route.
How long does it take to drive from Charlottenlund to Truskaw?
Approximately 12 h 44 min, assuming an 80 km/h average over an estimated road distance of 1019 km. Actual time depends on the route, traffic and border crossings.
How long is the flight from Charlottenlund to Truskaw?
A direct flight covers 816 km in about 1 h 28 min at typical cruise speed, plus airport time. Not all city pairs have direct flights.
How do I calculate distances for a whole list of locations?
Upload a CSV or Excel spreadsheet to the batch distance calculator — it computes the distance for every origin–destination row at once. The first records are free to try.
Related distances
Distance from Truskaw to Charlottenlund (reverse route)
GPS coordinates of Charlottenlund GPS coordinates of Truskaw